Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:00Z

11n² + 5n + 4 = 0

2H₂ + O₂ → 2H₂O

460K

iħ ∂ψ/∂t = Ĥψ

438K

∫₀^∞ e^(-x²) dx = √π / 2

N₂ + 3H₂ ⇌ 2NH₃

186K

ω = 2πf

411K

4φ² + 6φ + 2 = 0

∇²n = 0

448K

iħ ∂ψ/∂t = Ĥψ

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

\frac{12}{6} \sum_{i=1}^{n} i^{2}

459K

∑_{k=1}^{n} k = n(n+1)/2

406K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

181K

8ψ² + 7ψ + 0 = 0

80K

\frac{8}{7} \sum_{i=1}^{n} i^{2}

359K

∇²t = 0

455K