Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-20 04:37Z
∇²n = 0
∫₀^∞ e^(-θ²) dθ = √π / 2
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9r² + 4r + 1 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
det| 7 4 ; 4 8 | = 40
160K
11γ² + 3γ + 6 = 0
\lim_{ψ\to 0} \frac{\sin ψ}{ψ} = 1
∫₀^∞ e^(-ψ²) dψ = √π / 2
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