Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 04:03Z

e^{i\pi} + 1 = 0

N₂ + 3H₂ ⇌ 2NH₃

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∑_{k=1}^{n} k = n(n+1)/2

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

\oint_C \vec{F}\cdot d\vec{r} = 0

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8x² + 2x + 7 = 0

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\frac{1}{1} \sum_{i=1}^{n} i^{2}

N₂ + 3H₂ ⇌ 2NH₃

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det| 7 4 ; 4 8 | = 40

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λ = h/p

6t² + 6t + 4 = 0

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∇²t = 0

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∑_{k=1}^{n} k = n(n+1)/2

∑_{k=1}^{n} k = n(n+1)/2

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