Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:38Z

11n² + 5n + 4 = 0

∇²β = 0

460K

∑_{k=1}^{n} k = n(n+1)/2

438K

∫₀^∞ e^(-x²) dx = √π / 2

12n² + 2n + 2 = 0

186K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

411K

4φ² + 6φ + 2 = 0

\binom{n}{k} = \frac{n!}{k!(n-k)!}

448K

det| 7 4 ; 4 8 | = 40

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

11t² + 9t + 7 = 0

459K

iħ ∂ψ/∂t = Ĥψ

406K

∇²ω = 0

∇ × E = −∂B/∂t

181K

∫₀^∞ e^(-ψ²) dψ = √π / 2

80K

N₂ + 3H₂ ⇌ 2NH₃

359K

7r² + 8r + 5 = 0

455K