Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:09Z

10y² + 2y + 6 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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det| 7 4 ; 4 8 | = 40

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∫₀^∞ e^(-t²) dt = √π / 2

∇ × E = −∂B/∂t

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ω = 2πf

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e^{i\pi} + 1 = 0

det| 11 9 ; 0 12 | = 132

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\lim_{t\to 0} \frac{\sin t}{t} = 1

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

e^{i\pi} + 1 = 0

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\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

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∇²r = 0

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F = G m₁m₂ / r²

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N₂ + 3H₂ ⇌ 2NH₃

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∂γ/∂z = 6γ

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