Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:25Z

10y² + 2y + 6 = 0

F = ma

460K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

438K

∫₀^∞ e^(-t²) dt = √π / 2

λ = h/p

186K

d/dt [t^3] = 3t^2

411K

e^{i\pi} + 1 = 0

\frac{4}{9} \sum_{i=1}^{n} i^{2}

448K

∂γ/∂z = 6γ

22K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

∇²γ = 0

459K

iħ ∂ψ/∂t = Ĥψ

406K

∇ × E = −∂B/∂t

181K

\frac{8}{7} \sum_{i=1}^{n} i^{2}

80K

8ψ² + 7ψ + 0 = 0

359K