Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 04:18Z

∇²n = 0

12θ² + 2θ + 6 = 0

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∫₀^∞ e^(-ω²) dω = √π / 2

263K

9r² + 4r + 1 = 0

∇²z = 0

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8ψ² + 7ψ + 0 = 0

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

2n² + 4n + 0 = 0

333K

∇²γ = 0

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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PV = nRT

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det| 7 6 ; 1 8 | = 50

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∇ × E = −∂B/∂t

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d/dt [t^3] = 3t^2

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∫₀^∞ e^(-α²) dα = √π / 2

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