Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 00:42Z

d/dy [y^8] = 8y^7

\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

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N₂ + 3H₂ ⇌ 2NH₃

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\lim_{x\to 0} \frac{\sin x}{x} = 1

E = mc²

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d/dt [t^3] = 3t^2

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d/dn [n^3] = 3n^2

8ψ² + 7ψ + 0 = 0

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\frac{4}{9} \sum_{i=1}^{n} i^{2}

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6t² + 4t + 0 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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F = ma

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∑_{k=1}^{n} k = n(n+1)/2

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∇ × E = −∂B/∂t

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