Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:26Z

11n² + 5n + 4 = 0

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

460K

\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

438K

∫₀^∞ e^(-x²) dx = √π / 2

∫₀^∞ e^(-ω²) dω = √π / 2

186K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

411K

4φ² + 6φ + 2 = 0

F = G m₁m₂ / r²

448K

det| 7 4 ; 4 8 | = 40

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

8x² + 2x + 7 = 0

459K

∑_{k=1}^{n} k = n(n+1)/2

406K

∇²ω = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

181K

∑_{k=1}^{n} k = n(n+1)/2

80K

∇ × E = −∂B/∂t

359K