Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:56Z

11n² + 5n + 4 = 0

d/dt [t^3] = 3t^2

460K

PV = nRT

438K

∫₀^∞ e^(-x²) dx = √π / 2

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

186K

det| 9 4 ; 1 10 | = 86

411K

4φ² + 6φ + 2 = 0

iħ ∂ψ/∂t = Ĥψ

448K

det| 9 5 ; 1 10 | = 85

22K

∑_{k=1}^{n} k = n(n+1)/2

459K

iħ ∂ψ/∂t = Ĥψ

406K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

181K