Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:04Z

11n² + 5n + 4 = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

d/dt [t^3] = 3t^2

438K

∫₀^∞ e^(-x²) dx = √π / 2

CH₄ + 2O₂ → CO₂ + 2H₂O

186K

det| 3 1 ; 7 4 | = 5

411K

4φ² + 6φ + 2 = 0

∇²r = 0

448K

det| 9 4 ; 1 10 | = 86

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

det| 4 8 ; 3 5 | = -4

459K

∫₀^∞ e^(-t²) dt = √π / 2

406K

∇²ω = 0

∑_{k=1}^{n} k = n(n+1)/2

181K

\lim_{α\to 0} \frac{\sin α}{α} = 1

80K

d/dr [r^2] = 2r^1