Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 02:17Z

Fe₂O₃ + 3CO → 2Fe + 3CO₂

d/dt [t^3] = 3t^2

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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\frac{8}{4} \sum_{i=1}^{n} i^{2}

det| 1 4 ; 3 2 | = -10

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11z² + 3z + 4 = 0

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N₂ + 3H₂ ⇌ 2NH₃

\frac{12}{6} \sum_{i=1}^{n} i^{2}

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Fe₂O₃ + 3CO → 2Fe + 3CO₂

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2α² + 3α + 3 = 0

∂x/∂ψ = 6x

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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det| 10 7 ; 6 11 | = 68

∇ × E = −∂B/∂t

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8ψ² + 7ψ + 0 = 0

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2n² + 4n + 0 = 0

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