Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 04:47Z

∇²n = 0

det| 8 9 ; 4 9 | = 36

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det| 3 1 ; 7 4 | = 5

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9r² + 4r + 1 = 0

iħ ∂ψ/∂t = Ĥψ

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∑_{k=1}^{n} k = n(n+1)/2

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

iħ ∂ψ/∂t = Ĥψ

333K

F = G m₁m₂ / r²

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PV = nRT

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N₂ + 3H₂ ⇌ 2NH₃

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det| 12 1 ; 5 13 | = 151

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∫₀^∞ e^(-t²) dt = √π / 2

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8ψ² + 7ψ + 0 = 0

404K

\lim_{r\to 0} \frac{\sin r}{r} = 1

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