Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:03Z

10y² + 2y + 6 = 0

∫₀^∞ e^(-θ²) dθ = √π / 2

460K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

438K

∫₀^∞ e^(-t²) dt = √π / 2

det| 4 7 ; 2 5 | = 6

186K

d/dt [t^3] = 3t^2

411K

e^{i\pi} + 1 = 0

iħ ∂ψ/∂t = Ĥψ

448K

det| 12 1 ; 5 13 | = 151

22K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

det| 11 5 ; 0 12 | = 132

459K

∇²θ = 0

406K

∇ × E = −∂B/∂t

181K

∑_{k=1}^{n} k = n(n+1)/2

80K

8ψ² + 7ψ + 0 = 0

359K