Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:33Z

11n² + 5n + 4 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

460K

d/dφ [φ^1] = 1φ^0

438K

∫₀^∞ e^(-x²) dx = √π / 2

∫₀^∞ e^(-ω²) dω = √π / 2

186K

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

411K

4φ² + 6φ + 2 = 0

∑_{k=1}^{n} k = n(n+1)/2

448K

det| 7 4 ; 4 8 | = 40

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

N₂ + 3H₂ ⇌ 2NH₃

459K

Fe₂O₃ + 3CO → 2Fe + 3CO₂

406K

∇²ω = 0

∇²r = 0

181K

Fe₂O₃ + 3CO → 2Fe + 3CO₂

80K

N₂ + 3H₂ ⇌ 2NH₃

359K