Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 11:37Z

∇²t = 0

det| 10 2 ; 3 11 | = 104

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∑_{k=1}^{n} k = n(n+1)/2

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det| 6 4 ; 3 7 | = 30

det| 11 9 ; 0 12 | = 132

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∑_{k=1}^{n} k = n(n+1)/2

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ΔS ≥ 0

∇²γ = 0

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det| 7 4 ; 4 8 | = 40

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1z² + 3z + 2 = 0

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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7t² + 3t + 1 = 0

E = mc²

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∫₀^∞ e^(-ψ²) dψ = √π / 2

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N₂ + 3H₂ ⇌ 2NH₃

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∫₀^∞ e^(-α²) dα = √π / 2

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