Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 16:18Z

10γ² + 4γ + 3 = 0

∂ψ/∂β = 3ψ

460K

PV = nRT

438K

d/dβ [β^11] = 11β^10

∑_{k=1}^{n} k = n(n+1)/2

186K

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

411K

3x² + 4x + 6 = 0

10ψ² + 5ψ + 0 = 0

448K

det| 7 4 ; 4 8 | = 40

22K

N₂ + 3H₂ ⇌ 2NH₃

459K

\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

406K

∑_{k=1}^{n} k = n(n+1)/2

181K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

80K

E = mc²

359K