Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 15:19Z
11n² + 5n + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
438K
∫₀^∞ e^(-x²) dx = √π / 2
4φ² + 6φ + 2 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
448K
det| 5 2 ; 3 6 | = 24
22K
∫₀^∞ e^(-φ²) dφ = √π / 2
∑_{k=1}^{n} k = n(n+1)/2
459K
∑_{k=1}^{n} k = n(n+1)/2
181K
det| 7 4 ; 4 8 | = 40
80K