Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 15:36Z
11n² + 5n + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
438K
∫₀^∞ e^(-x²) dx = √π / 2
∑_{k=1}^{n} k = n(n+1)/2
411K
4φ² + 6φ + 2 = 0
det| 7 4 ; 4 8 | = 40
448K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
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det| 2 6 ; 0 3 | = 6
359K