Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:40Z

11n² + 5n + 4 = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

d/dt [t^3] = 3t^2

438K

∫₀^∞ e^(-x²) dx = √π / 2

e^{i\pi} + 1 = 0

186K

det| 9 4 ; 1 10 | = 86

411K

4φ² + 6φ + 2 = 0

5z² + 8z + 3 = 0

448K

N₂ + 3H₂ ⇌ 2NH₃

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

∇²β = 0

459K

∇²t = 0

406K

ΔS ≥ 0

181K

∑_{k=1}^{n} k = n(n+1)/2

80K

\binom{n}{k} = \frac{n!}{k!(n-k)!}

359K