Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:09Z

10y² + 2y + 6 = 0

PV = nRT

460K

∑_{k=1}^{n} k = n(n+1)/2

438K

∫₀^∞ e^(-t²) dt = √π / 2

iħ ∂ψ/∂t = Ĥψ

186K

e^{i\pi} + 1 = 0

411K

e^{i\pi} + 1 = 0

N₂ + 3H₂ ⇌ 2NH₃

448K

det| 7 4 ; 4 8 | = 40

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

459K

\oint_C \vec{F}\cdot d\vec{r} = 0

406K

λ = h/p

iħ ∂ψ/∂t = Ĥψ

d/dγ [γ^3] = 3γ^2