Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 06:07Z

∑_{k=1}^{n} k = n(n+1)/2

e^{i\pi} + 1 = 0

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iħ ∂ψ/∂t = Ĥψ

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e^{i\pi} + 1 = 0

iħ ∂ψ/∂t = Ĥψ

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det| 7 4 ; 4 8 | = 40

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2H₂ + O₂ → 2H₂O

F = G m₁m₂ / r²

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\frac{4}{9} \sum_{i=1}^{n} i^{2}

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det| 4 8 ; 0 5 | = 20

11z² + 3z + 4 = 0

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∑_{k=1}^{n} k = n(n+1)/2

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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

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∇ × E = −∂B/∂t

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