Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:25Z

10y² + 2y + 6 = 0

∇ × E = −∂B/∂t

460K

PV = nRT

438K

∫₀^∞ e^(-t²) dt = √π / 2

\frac{4}{6} \sum_{i=1}^{n} i^{2}

186K

5φ² + 1φ + 1 = 0

411K

e^{i\pi} + 1 = 0

PV = nRT

448K

d/dt [t^3] = 3t^2

22K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

∫₀^∞ e^(-x²) dx = √π / 2

459K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

406K

λ = h/p

8ψ² + 7ψ + 0 = 0

181K

N₂ + 3H₂ ⇌ 2NH₃

80K

d/dγ [γ^3] = 3γ^2