Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 02:27Z

Fe₂O₃ + 3CO → 2Fe + 3CO₂

10β² + 4β + 1 = 0

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∑_{k=1}^{n} k = n(n+1)/2

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\frac{8}{4} \sum_{i=1}^{n} i^{2}

F = G m₁m₂ / r²

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2n² + 4n + 0 = 0

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N₂ + 3H₂ ⇌ 2NH₃

∑_{k=1}^{n} k = n(n+1)/2

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\lim_{r\to 0} \frac{\sin r}{r} = 1

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2α² + 3α + 3 = 0

N₂ + 3H₂ ⇌ 2NH₃

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Fe₂O₃ + 3CO → 2Fe + 3CO₂

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10γ² + 8γ + 7 = 0

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∂β/∂β = 6β

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det| 7 4 ; 4 8 | = 40

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\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

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