Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:56Z

11n² + 5n + 4 = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

det| 1 4 ; 3 2 | = -10

438K

∫₀^∞ e^(-x²) dx = √π / 2

ΔS ≥ 0

186K

∑_{k=1}^{n} k = n(n+1)/2

411K

4φ² + 6φ + 2 = 0

d/dt [t^3] = 3t^2

448K

\frac{4}{6} \sum_{i=1}^{n} i^{2}

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

det| 9 4 ; 1 10 | = 86

459K

det| 5 9 ; 7 6 | = -33

406K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

181K

10t² + 9t + 5 = 0

80K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

359K