Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 02:51Z

Fe₂O₃ + 3CO → 2Fe + 3CO₂

8ψ² + 7ψ + 0 = 0

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8θ² + 8θ + 6 = 0

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\frac{8}{4} \sum_{i=1}^{n} i^{2}

d/dt [t^3] = 3t^2

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2H₂ + O₂ → 2H₂O

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N₂ + 3H₂ ⇌ 2NH₃

Fe₂O₃ + 3CO → 2Fe + 3CO₂

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∇ × E = −∂B/∂t

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\frac{2}{2} \sum_{i=1}^{n} i^{2}

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∑_{k=1}^{n} k = n(n+1)/2

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6ω² + 4ω + 4 = 0

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