Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-20 04:47Z
∇²n = 0
∑_{k=1}^{n} k = n(n+1)/2
273K
9r² + 4r + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
139K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
333K
11γ² + 3γ + 6 = 0
det| 12 1 ; 5 13 | = 151
413K
\lim_{ψ\to 0} \frac{\sin ψ}{ψ} = 1
det| 9 4 ; 1 10 | = 86
297K
det| 6 1 ; 3 7 | = 39
det| 3 1 ; 7 4 | = 5
404K
e^{i\pi} + 1 = 0