Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 04:48Z

∇²n = 0

1n² + 7n + 3 = 0

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∂y/∂n = 5y

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9r² + 4r + 1 = 0

ΔS ≥ 0

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∑_{k=1}^{n} k = n(n+1)/2

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

det| 7 4 ; 4 8 | = 40

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iħ ∂ψ/∂t = Ĥψ

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11γ² + 3γ + 6 = 0

N₂ + 3H₂ ⇌ 2NH₃

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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N₂ + 3H₂ ⇌ 2NH₃

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det| 2 3 ; 5 3 | = -9

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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