Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:22Z

11n² + 5n + 4 = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

PV = nRT

438K

∫₀^∞ e^(-x²) dx = √π / 2

\frac{12}{6} \sum_{i=1}^{n} i^{2}

186K

det| 4 7 ; 2 5 | = 6

411K

4φ² + 6φ + 2 = 0

det| 3 6 ; 0 4 | = 12

448K

det| 7 4 ; 4 8 | = 40

22K

N₂ + 3H₂ ⇌ 2NH₃

459K

CH₄ + 2O₂ → CO₂ + 2H₂O

406K

∑_{k=1}^{n} k = n(n+1)/2

181K

\lim_{r\to 0} \frac{\sin r}{r} = 1

80K

5φ² + 1φ + 1 = 0

359K