Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-20 04:47Z
∇²n = 0
∑_{k=1}^{n} k = n(n+1)/2
263K
9r² + 4r + 1 = 0
∫₀^∞ e^(-α²) dα = √π / 2
139K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∫₀^∞ e^(-t²) dt = √π / 2
333K
det| 10 7 ; 3 11 | = 89
160K
11γ² + 3γ + 6 = 0
\oint_C \vec{F}\cdot d\vec{r} = 0
413K
\lim_{ψ\to 0} \frac{\sin ψ}{ψ} = 1
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
297K
det| 7 4 ; 4 8 | = 40
128K
det| 6 1 ; 3 7 | = 39
e^{i\pi} + 1 = 0
N₂ + 3H₂ ⇌ 2NH₃
∑_{k=1}^{n} k = n(n+1)/2