Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 17:44Z

det| 11 2 ; 2 12 | = 128

det| 2 6 ; 0 3 | = 6

460K

∇ × E = −∂B/∂t

438K

CaCO₃ → CaO + CO₂

∑_{k=1}^{n} k = n(n+1)/2

186K

N₂ + 3H₂ ⇌ 2NH₃

411K

3θ² + 7θ + 1 = 0

CH₄ + 2O₂ → CO₂ + 2H₂O

448K

e^{i\pi} + 1 = 0

22K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

\lim_{t\to 0} \frac{\sin t}{t} = 1

459K

6t² + 6t + 4 = 0

406K

d/dt [t^3] = 3t^2

181K

det| 8 9 ; 4 9 | = 36

80K

\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

359K

8ψ² + 7ψ + 0 = 0

455K