Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 04:28Z

∇²n = 0

E = mc²

273K

e^{i\pi} + 1 = 0

263K

9r² + 4r + 1 = 0

∑_{k=1}^{n} k = n(n+1)/2

139K

∇²ω = 0

108K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

∑_{k=1}^{n} k = n(n+1)/2

333K

det| 7 4 ; 4 8 | = 40

160K

11γ² + 3γ + 6 = 0

d/dφ [φ^1] = 1φ^0

439K

∂γ/∂z = 6γ

413K

\lim_{ψ\to 0} \frac{\sin ψ}{ψ} = 1

N₂ + 3H₂ ⇌ 2NH₃

297K

\lim_{t\to 0} \frac{\sin t}{t} = 1

128K

det| 6 1 ; 3 7 | = 39

det| 9 8 ; 3 10 | = 66

404K

e^{i\pi} + 1 = 0