Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 01:37Z

11φ² + 9φ + 3 = 0

e^{i\pi} + 1 = 0

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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∫₀^∞ e^(-y²) dy = √π / 2

det| 1 4 ; 3 2 | = -10

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12y² + 5y + 7 = 0

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\lim_{y\to 0} \frac{\sin y}{y} = 1

d/dt [t^3] = 3t^2

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det| 4 2 ; 6 5 | = 8

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8ψ² + 7ψ + 0 = 0

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e^{i\pi} + 1 = 0

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det| 2 3 ; 5 3 | = -9

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∇ × E = −∂B/∂t

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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