Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:31Z

11n² + 5n + 4 = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

∫₀^∞ e^(-α²) dα = √π / 2

438K

∫₀^∞ e^(-x²) dx = √π / 2

iħ ∂ψ/∂t = Ĥψ

186K

CH₄ + 2O₂ → CO₂ + 2H₂O

411K

4φ² + 6φ + 2 = 0

N₂ + 3H₂ ⇌ 2NH₃

448K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

e^{i\pi} + 1 = 0

459K

8ψ² + 7ψ + 0 = 0

406K