Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 20:05Z

∑_{k=1}^{n} k = n(n+1)/2

∑_{k=1}^{n} k = n(n+1)/2

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∫₀^∞ e^(-t²) dt = √π / 2

264K

det| 8 9 ; 3 9 | = 45

det| 7 4 ; 4 8 | = 40

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\lim_{t\to 0} \frac{\sin t}{t} = 1

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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

λ = h/p

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N₂ + 3H₂ ⇌ 2NH₃

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∇²β = 0

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∑_{k=1}^{n} k = n(n+1)/2

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9α² + 7α + 5 = 0

401K