Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 16:18Z

10γ² + 4γ + 3 = 0

Fe₂O₃ + 3CO → 2Fe + 3CO₂

460K

∑_{k=1}^{n} k = n(n+1)/2

438K

d/dβ [β^11] = 11β^10

∂x/∂ψ = 6x

186K

E = mc²

411K

3x² + 4x + 6 = 0

\lim_{r\to 0} \frac{\sin r}{r} = 1

448K

d/dt [t^3] = 3t^2

22K

CaCO₃ → CaO + CO₂

9θ² + 7θ + 4 = 0

459K

1θ² + 2θ + 6 = 0

406K

Fe₂O₃ + 3CO → 2Fe + 3CO₂

8θ² + 8θ + 6 = 0

181K

∫₀^∞ e^(-ψ²) dψ = √π / 2

80K

det| 9 4 ; 1 10 | = 86

359K

6ω² + 4ω + 4 = 0

455K