Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:59Z

11n² + 5n + 4 = 0

det| 3 6 ; 0 4 | = 12

460K

∇ × E = −∂B/∂t

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∫₀^∞ e^(-x²) dx = √π / 2

e^{i\pi} + 1 = 0

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

411K

4φ² + 6φ + 2 = 0

d/dt [t^3] = 3t^2

448K

\binom{n}{k} = \frac{n!}{k!(n-k)!}

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∫₀^∞ e^(-φ²) dφ = √π / 2

Fe₂O₃ + 3CO → 2Fe + 3CO₂

459K

e^{i\pi} + 1 = 0

406K

∇²ω = 0

8ψ² + 7ψ + 0 = 0

181K

N₂ + 3H₂ ⇌ 2NH₃

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d/dr [r^2] = 2r^1

∑_{k=1}^{n} k = n(n+1)/2

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iħ ∂ψ/∂t = Ĥψ

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