Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 11:37Z

∇²t = 0

∇ × E = −∂B/∂t

460K

det| 10 2 ; 3 11 | = 104

438K

det| 6 4 ; 3 7 | = 30

\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

186K

5φ² + 1φ + 1 = 0

411K

ΔS ≥ 0

d/dt [t^3] = 3t^2

448K

8ψ² + 7ψ + 0 = 0

22K

1z² + 3z + 2 = 0

\lim_{t\to 0} \frac{\sin t}{t} = 1

459K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

406K

7t² + 3t + 1 = 0

det| 3 6 ; 0 4 | = 12

181K

det| 11 5 ; 2 12 | = 122

det| 8 3 ; 4 9 | = 60

10γ² + 8γ + 2 = 0

∇ × E = −∂B/∂t

λ = h/p