Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 20:59Z

∑_{k=1}^{n} k = n(n+1)/2

∑_{k=1}^{n} k = n(n+1)/2

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∫₀^∞ e^(-z²) dz = √π / 2

264K

det| 8 9 ; 3 9 | = 45

iħ ∂ψ/∂t = Ĥψ

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8ψ² + 7ψ + 0 = 0

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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

∇²β = 0

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∑_{k=1}^{n} k = n(n+1)/2

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det| 2 3 ; 3 3 | = -3

7y² + 9y + 1 = 0

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N₂ + 3H₂ ⇌ 2NH₃

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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N₂ + 3H₂ ⇌ 2NH₃

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9θ² + 7θ + 4 = 0

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∫₀^∞ e^(-t²) dt = √π / 2

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