Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:02Z

11n² + 5n + 4 = 0

d/dt [t^3] = 3t^2

460K

∇²r = 0

438K

∫₀^∞ e^(-x²) dx = √π / 2

∇ × E = −∂B/∂t

186K

∂β/∂β = 6β

411K

4φ² + 6φ + 2 = 0

∂y/∂n = 5y

448K

8ψ² + 7ψ + 0 = 0

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

CH₄ + 2O₂ → CO₂ + 2H₂O

459K

det| 5 6 ; 2 6 | = 18

406K

∇²ω = 0

det| 4 7 ; 2 5 | = 6

181K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

80K

d/dr [r^2] = 2r^1

∑_{k=1}^{n} k = n(n+1)/2

359K