Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 04:19Z

∇²n = 0

PV = nRT

273K

N₂ + 3H₂ ⇌ 2NH₃

263K

9r² + 4r + 1 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

139K

2n² + 4n + 0 = 0

108K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

det| 7 4 ; 4 8 | = 40

333K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

160K

11γ² + 3γ + 6 = 0

∑_{k=1}^{n} k = n(n+1)/2

439K

∑_{k=1}^{n} k = n(n+1)/2

413K

7r² + 8r + 5 = 0

297K

∫₀^∞ e^(-t²) dt = √π / 2

128K