Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:54Z

11n² + 5n + 4 = 0

PV = nRT

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∫₀^∞ e^(-θ²) dθ = √π / 2

438K

∫₀^∞ e^(-x²) dx = √π / 2

det| 5 2 ; 3 6 | = 24

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12y² + 5y + 7 = 0

411K

4φ² + 6φ + 2 = 0

d/dt [t^3] = 3t^2

448K

\lim_{t\to 0} \frac{\sin t}{t} = 1

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8ψ² + 7ψ + 0 = 0

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∂ψ/∂β = 3ψ

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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∇ × E = −∂B/∂t

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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