Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 04:25Z

∇²n = 0

F = G m₁m₂ / r²

273K

∇²z = 0

263K

9r² + 4r + 1 = 0

\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

139K

e^{i\pi} + 1 = 0

108K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

∇ × E = −∂B/∂t

333K

∫₀^∞ e^(-θ²) dθ = √π / 2

160K

11γ² + 3γ + 6 = 0

N₂ + 3H₂ ⇌ 2NH₃

439K

det| 7 4 ; 4 8 | = 40

413K

\lim_{ψ\to 0} \frac{\sin ψ}{ψ} = 1

det| 12 6 ; 6 13 | = 120