Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 14:52Z

3γ² + 8γ + 4 = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

∫₀^∞ e^(-θ²) dθ = √π / 2

438K

PV = nRT

d/dx [x^9] = 9x^8

186K

7y² + 9y + 1 = 0

411K

det| 1 9 ; 5 2 | = -43

∇²θ = 0

448K

d/dt [t^3] = 3t^2

22K

ω = 2πf

det| 9 4 ; 1 10 | = 86

459K

∑_{k=1}^{n} k = n(n+1)/2

406K

∂n/∂ψ = 6n

∑_{k=1}^{n} k = n(n+1)/2

181K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

80K

N₂ + 3H₂ ⇌ 2NH₃

iħ ∂ψ/∂t = Ĥψ

359K