Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 17:16Z

PV = nRT

∑_{k=1}^{n} k = n(n+1)/2

451K

det| 7 4 ; 4 8 | = 40

264K

8t² + 4t + 4 = 0

N₂ + 3H₂ ⇌ 2NH₃

297K

det| 5 6 ; 2 6 | = 18

252K

F = ma

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

48K

N₂ + 3H₂ ⇌ 2NH₃

411K

det| 7 6 ; 2 8 | = 44

PV = nRT

377K

∑_{k=1}^{n} k = n(n+1)/2

299K

2γ² + 2γ + 6 = 0

∑_{k=1}^{n} k = n(n+1)/2

401K

N₂ + 3H₂ ⇌ 2NH₃

420K

4φ² + 3φ + 1 = 0