Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-19 20:09Z
∑_{k=1}^{n} k = n(n+1)/2
det| 11 9 ; 0 12 | = 132
451K
det| 8 9 ; 3 9 | = 45
∑_{k=1}^{n} k = n(n+1)/2
252K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
det| 4 7 ; 2 5 | = 6
411K
det| 9 4 ; 1 10 | = 86
299K
∫₀^∞ e^(-t²) dt = √π / 2
420K
∑_{k=1}^{n} k = n(n+1)/2
109K