Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-19 16:23Z
∂ψ/∂φ = 6ψ
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
451K
11ψ² + 2ψ + 6 = 0
λ = h/p
\frac{9}{7} \sum_{i=1}^{n} i^{2}
\frac{2}{8} \sum_{i=1}^{n} i^{2}
\frac{10}{3} \sum_{i=1}^{n} i^{2}
d/dt [t^4] = 4t^3