Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:31Z

11n² + 5n + 4 = 0

\frac{2}{2} \sum_{i=1}^{n} i^{2}

460K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

438K

∫₀^∞ e^(-x²) dx = √π / 2

6n² + 7n + 6 = 0

186K

∇ × E = −∂B/∂t

411K

4φ² + 6φ + 2 = 0

7γ² + 8γ + 3 = 0

448K

∑_{k=1}^{n} k = n(n+1)/2

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

det| 9 8 ; 3 10 | = 66

459K

8ψ² + 7ψ + 0 = 0

406K

det| 2 8 ; 7 3 | = -50

181K

d/dt [t^3] = 3t^2

80K

det| 8 9 ; 4 9 | = 36

359K