Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 03:08Z

e^{i\pi} + 1 = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

N₂ + 3H₂ ⇌ 2NH₃

438K

F = ma

det| 11 4 ; 5 12 | = 112

186K

5z² + 8z + 3 = 0

411K

12θ² + 8θ + 3 = 0

∑_{k=1}^{n} k = n(n+1)/2

448K

det| 7 4 ; 4 8 | = 40

22K

ω = 2πf

e^{i\pi} + 1 = 0

459K

\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

406K

N₂ + 3H₂ ⇌ 2NH₃

∇²x = 0

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂