Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:58Z

11n² + 5n + 4 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

460K

6ω² + 4ω + 4 = 0

438K

∫₀^∞ e^(-x²) dx = √π / 2

∫₀^∞ e^(-ω²) dω = √π / 2

186K

det| 11 4 ; 5 12 | = 112

411K

4φ² + 6φ + 2 = 0

F = G m₁m₂ / r²

448K

det| 7 4 ; 4 8 | = 40

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

8θ² + 8θ + 6 = 0

459K

\binom{n}{k} = \frac{n!}{k!(n-k)!}

406K

∇²ω = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

181K

e^{i\pi} + 1 = 0

80K

∇ × E = −∂B/∂t

359K